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2x^2+17x-4.9=0
a = 2; b = 17; c = -4.9;
Δ = b2-4ac
Δ = 172-4·2·(-4.9)
Δ = 328.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{328.2}}{2*2}=\frac{-17-\sqrt{328.2}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{328.2}}{2*2}=\frac{-17+\sqrt{328.2}}{4} $
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